Question

Какое количество вещества оксида олова расходуется на реакцию 11,2 л водорода

Answer 1

Ответ:

Объяснение:

11,2 л              Х моль

 2H2      +      SnO2     ->     Sn     +    2H2O

n=2 моль          n=1 моль

Vm=22,4 л/моль

V = 44,8 л

11,2 л  Н2    -    Х моль   SnO2

44,8 л  Н2   -   1 моль     SnO2

n(SnO2) = 11,2 *1 / 44,8 = 0,25 моль

Answer 2

Reaction Stoichiometry

To calculate the amount of substance of tin oxide (SnO2) required for the reaction with 11.2 L of hydrogen gas (H2), we can use the balanced chemical equation for the reaction between tin oxide and hydrogen gas.

The balanced chemical equation for the reaction is: SnO2 + 2H2 → Sn + 2H2O

From the balanced equation, we can see that 1 mole of SnO2 reacts with 2 moles of H2.

Calculation

To find the amount of SnO2 required, we can use the following steps:

1. Convert the given volume of hydrogen gas to moles using the ideal gas law. 2. Use the mole ratio from the balanced chemical equation to find the moles of SnO2 required. 3. Convert the moles of SnO2 to the required mass using the molar mass of SnO2.

Step 1: Convert Volume of Hydrogen Gas to Moles

The ideal gas law is given by the equation: PV = nRT

Where: - P = pressure - V = volume - n = number of moles - R = ideal gas constant - T = temperature

Given: - Volume of hydrogen gas (V) = 11.2 L - Standard temperature and pressure (STP) conditions: T = 273 K, P = 1 atm

Using the ideal gas law, we can calculate the number of moles of hydrogen gas.

Step 2: Use Mole Ratio to Find Moles of SnO2

From the balanced chemical equation, we know that 1 mole of SnO2 reacts with 2 moles of H2. Therefore, the moles of SnO2 required can be calculated using the mole ratio.

Step 3: Convert Moles of SnO2 to Mass

The molar mass of SnO2 can be used to convert moles of SnO2 to the required mass.

Conclusion

By following these steps, we can calculate the amount of substance of tin oxide (SnO2) required for the reaction with 11.2 L of hydrogen gas.