Question

Какая масса хлорида кальция образует при взаимодействии 5,6 г оксида кальция с необходимым количеством соляной кислоты

Answer 1

CaO + 2HCl = CaCl2 + H2O

Дано:

m(CaO) = 5,6г

m(CaCl2) -?

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Решение:

n(CaO) = 5,6 / 56 = 0,1 моль

n(CaO) = n(CaCl2) = 0,1 моль

m(CaCl2) = 0,1 * 111 = 11,1 г

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Ответ: m(CaCl2) = 11,1 г

Answer 2

Calculating the Mass of Calcium Chloride Formed

When 5.6 g of calcium oxide reacts with the necessary amount of hydrochloric acid, calcium chloride is formed. To calculate the mass of calcium chloride formed, we can use the stoichiometry of the reaction.

The balanced chemical equation for the reaction between calcium oxide and hydrochloric acid is:

CaO + 2HCl → CaCl2 + H2O

From the balanced equation, we can see that 1 mole of calcium oxide reacts with 2 moles of hydrochloric acid to produce 1 mole of calcium chloride.

Using the molar masses: - Calcium oxide (CaO) has a molar mass of approximately 56.08 g/mol. - Calcium chloride (CaCl2) has a molar mass of approximately 110.98 g/mol.

Now, let's calculate the mass of calcium chloride formed.

First, we need to find the number of moles of calcium oxide: Number of moles = Mass / Molar mass Number of moles of CaO = 5.6 g / 56.08 g/mol = 0.1 mol

According to the stoichiometry of the reaction, 1 mole of CaO produces 1 mole of CaCl2. Therefore, the number of moles of CaCl2 formed is also 0.1 mol.

Finally, we can calculate the mass of calcium chloride formed: Mass = Number of moles × Molar mass Mass of CaCl2 = 0.1 mol × 110.98 g/mol = 11.098 g

So, when 5.6 g of calcium oxide reacts with the necessary amount of hydrochloric acid, the mass of calcium chloride formed is approximately 11.098 g.