Question

Порахуйте відносну молекулярну масу Mn2o3

Answer 1

Ответ:

158

Объяснение:

Ar(Mn) × 2 + Ar(O)× 3= 55*2+16*3=158

Answer 2

Calculating the Relative Molecular Mass of Mn2O3

To calculate the relative molecular mass of Mn2O3, we need to consider the atomic masses of the elements involved and their respective subscripts in the chemical formula.

The relative atomic masses of the elements are as follows: - Manganese (Mn) has a relative atomic mass of 54.94. - Oxygen (O) has a relative atomic mass of 16.00.

Using these atomic masses, we can calculate the relative molecular mass of Mn2O3.

The chemical formula Mn2O3 indicates that there are 2 atoms of manganese and 3 atoms of oxygen in each molecule of Mn2O3.

Calculation:

The relative molecular mass (M) of Mn2O3 can be calculated using the formula: M = (2 * atomic mass of Mn) + (3 * atomic mass of O)

Substituting the values: M = (2 * 54.94) + (3 * 16.00) M = 109.88 + 48.00 M = 157.88

The relative molecular mass of Mn2O3 is 157.88.