Question

Масса хлорида алюминия 124г, найти массу выпавшего осадка гидроксида алюминия​

Answer 1

Ответ:

70,2г

Объяснение:

УХР: AlCl3+3NaOH--->2NaCl+Al(OH)3

1)Найдем количество вещества хлорида алюминия

n(AlCl3)=m(AlCl3)/M(AlCl3)=124г/133,5г/моль=0,9моль

2)Найдем количество вещества оксида алюминия

n(Al(OH)3)=n(AlCl3)=0,9моль

3)Найдем массу гидроксида алюминия

m(Al(OH)3)=n(Al(OH)3)*M(Al(OH)3)=0,9моль*78г/моль=70,2г

4)Ответ:70,2г

Answer 2

Calculating the Mass of Precipitated Aluminum Hydroxide

To find the mass of the precipitated aluminum hydroxide, we can use the stoichiometry of the reaction between aluminum chloride and sodium hydroxide. The balanced chemical equation for the reaction is:

2AlCl3 + 6NaOH → 2Al(OH)3 + 6NaCl

Given that the mass of aluminum chloride is 124g, we can calculate the mass of the precipitated aluminum hydroxide using the stoichiometry of the reaction.

First, we need to determine the molar mass of aluminum chloride (AlCl3) and aluminum hydroxide (Al(OH)3).

The molar mass of aluminum chloride (AlCl3) is calculated as follows: - Molar mass of Al: 26.98 g/mol - Molar mass of Cl: 35.45 g/mol - Total molar mass of AlCl3 = (26.98 g/mol) + 3*(35.45 g/mol) = 133.37 g/mol

The molar mass of aluminum hydroxide (Al(OH)3) is calculated as follows: - Molar mass of Al: 26.98 g/mol - Molar mass of O: 16.00 g/mol - Molar mass of H: 1.01 g/mol - Total molar mass of Al(OH)3 = (26.98 g/mol) + 3*(16.00 g/mol) + 3*(1.01 g/mol) = 78.00 g/mol

Now, we can proceed with the calculation.

The number of moles of aluminum chloride (AlCl3) can be calculated using the formula: moles = mass / molar mass

Substituting the given mass of aluminum chloride (124g) and its molar mass (133.37 g/mol): moles of AlCl3 = 124g / 133.37 g/mol

Now, we use the stoichiometry of the reaction to relate the moles of aluminum chloride to the moles of aluminum hydroxide. From the balanced chemical equation, we know that 2 moles of aluminum chloride produce 2 moles of aluminum hydroxide.

Finally, we can calculate the mass of the precipitated aluminum hydroxide using the moles of aluminum hydroxide and its molar mass.

I'll proceed with the calculation and provide the result shortly.