Question

при взаимодействии 500 г известняка с раствором соляной кислоты выделилось 0,5л углекислого газа. определите массовую долю карбоната кальция в образце известняка​

Answer 1

CaCO3 + 2HCl = CaCl2 + CO2 + H2O

n(CO2) = 0,02 моль

n(CaCO3) = 5 моль

n(CaCO3)прореагировало= 0,02моль

m ( CaCO3) = 0,02*100= 2г

W(CaCO3) = 2/500= 0,4%

Answer 2

Mass Fraction of Calcium Carbonate in Limestone

When 500 g of limestone interacts with hydrochloric acid, resulting in the release of 0.5 L of carbon dioxide gas, we can determine the mass fraction of calcium carbonate in the limestone.

The mass fraction of calcium carbonate can be calculated using the following formula:

Mass fraction of calcium carbonate = (mass of carbon dioxide gas / molar mass of carbon dioxide) / (mass of limestone)

First, let's calculate the mass of carbon dioxide gas released. The molar mass of carbon dioxide (CO2) is approximately 44.01 g/mol.

Mass of carbon dioxide gas = volume of carbon dioxide gas * density of carbon dioxide at given conditions

Given that the volume of carbon dioxide gas released is 0.5 L, and the density of carbon dioxide at the given conditions, we can calculate the mass of carbon dioxide gas.

Next, we can calculate the mass fraction of calcium carbonate in the limestone using the formula mentioned earlier.

Let's proceed with the calculations.