Question

Допоможіть будь ласка Знайдіть помилку4)4Na+4H2O=4NaOH+2H2 5)Ca+O2=Ca2O 6)2Fe+2Cl2=2FеCl3 7)CaCO3=CaO+2CO2 8)Cu(OH)2=CuO+H2O

Answer 1

Объяснение:

Не правильно роставлены индексы и коефіцієнты

Answer 2

Balancing Chemical Equations

Let's balance the given chemical equations:

1) 4Na + 4H2O = 4NaOH + 2H2

To balance this equation, we need to ensure that the number of atoms of each element is the same on both sides of the equation.

On the left side, we have 4 sodium (Na) atoms and 8 hydrogen (H) atoms. On the right side, we have 4 sodium (Na) atoms, 4 oxygen (O) atoms, and 2 hydrogen (H) atoms.

To balance the hydrogen (H) atoms, we can place a coefficient of 4 in front of the water (H2O) on the left side:

4Na + 4H2O = 4NaOH + 2H2

Now, we have 8 hydrogen (H) atoms on both sides.

To balance the oxygen (O) atoms, we can place a coefficient of 2 in front of the sodium hydroxide (NaOH) on the right side:

4Na + 4H2O = 4NaOH + 2H2

Now, we have 4 oxygen (O) atoms on both sides.

The balanced equation is:

4Na + 4H2O = 4NaOH + 2H2

2) Ca + O2 = Ca2O

To balance this equation, we need to ensure that the number of atoms of each element is the same on both sides of the equation.

On the left side, we have 1 calcium (Ca) atom and 2 oxygen (O) atoms. On the right side, we have 2 calcium (Ca) atoms and 1 oxygen (O) atom.

To balance the calcium (Ca) atoms, we can place a coefficient of 2 in front of the calcium (Ca) on the left side:

2Ca + O2 = Ca2O

Now, we have 2 calcium (Ca) atoms on both sides.

The balanced equation is:

2Ca + O2 = Ca2O

3) 2Fe + 2Cl2 = 2FeCl3

To balance this equation, we need to ensure that the number of atoms of each element is the same on both sides of the equation.

On the left side, we have 2 iron (Fe) atoms and 4 chlorine (Cl) atoms. On the right side, we have 2 iron (Fe) atoms and 6 chlorine (Cl) atoms.

To balance the chlorine (Cl) atoms, we can place a coefficient of 3 in front of the iron(III) chloride (FeCl3) on the right side:

2Fe + 2Cl2 = 2FeCl3

Now, we have 6 chlorine (Cl) atoms on both sides.

The balanced equation is:

2Fe + 2Cl2 = 2FeCl3

4) CaCO3 = CaO + 2CO2

To balance this equation, we need to ensure that the number of atoms of each element is the same on both sides of the equation.

On the left side, we have 1 calcium (Ca) atom, 1 carbon (C) atom, and 3 oxygen (O) atoms. On the right side, we have 1 calcium (Ca) atom, 2 carbon (C) atoms, and 4 oxygen (O) atoms.

To balance the carbon (C) atoms, we can place a coefficient of 2 in front of the carbon dioxide (CO2) on the right side:

CaCO3 = CaO + 2CO2

Now, we have 2 carbon (C) atoms on both sides.

The balanced equation is:

CaCO3 = CaO + 2CO2

5) Cu(OH)2 = CuO + H2O

To balance this equation, we need to ensure that the number of atoms of each element is the same on both sides of the equation.

On the left side, we have 1 copper (Cu) atom, 2 oxygen (O) atoms, and 4 hydrogen (H) atoms. On the right side, we have 1 copper (Cu) atom, 1 oxygen (O) atom, and 2 hydrogen (H) atoms.

To balance the hydrogen (H) atoms, we can place a coefficient of 2 in front of the water (H2O) on the right side:

Cu(OH)2 = CuO + 2H2O

Now, we have 4 hydrogen (H) atoms on both sides.

The balanced equation is:

Cu(OH)2 = CuO + 2H2O

I hope this helps! Let me know if you have any further questions.