Question

Яку масу етилетаноату можна добути із 20 оцтової есенції що містить 25% води?

Answer 1

20•25%(0,25)=5

набьюсь правильно

Answer 2

Calculating the Mass of Ethyl Ethanoate

To calculate the mass of ethyl ethanoate that can be obtained from 20 mL of acetic acid (vinegar) containing 25% water, we can use the concept of stoichiometry and the molar masses of the substances involved.

First, we need to determine the amount of acetic acid in the solution and then use stoichiometry to find the mass of ethyl ethanoate that can be produced.

Step 1: Calculate the Amount of Acetic Acid

The concentration of acetic acid in the solution can be calculated using the given information. Since the solution contains 25% water, the remaining 75% is acetic acid.

Calculation: - 20 mL of solution * 0.75 (to account for the 75% acetic acid) = amount of acetic acid in the solution

Step 2: Convert Volume to Mass

Next, we need to convert the volume of acetic acid to mass using the density of acetic acid.

Search Result 1: - The density of acetic acid is approximately 1.049 g/mL at 20°C [[1]].

Step 3: Use Stoichiometry to Find the Mass of Ethyl Ethanoate

The balanced chemical equation for the reaction between acetic acid and ethanol to produce ethyl ethanoate is:

CH3COOH + C2H5OH → CH3COOC2H5 + H2O

From the balanced equation, we can determine the stoichiometry of the reaction and use it to calculate the mass of ethyl ethanoate produced.

Search Result 2: - The molar mass of acetic acid (CH3COOH) is approximately 60.05 g/mol, and the molar mass of ethyl ethanoate (CH3COOC2H5) is approximately 88.11 g/mol [[2]].

Step 4: Perform the Calculation

Using the molar masses and stoichiometry, we can calculate the mass of ethyl ethanoate produced from the given amount of acetic acid.

I will now perform the calculations and provide you with the result.