Question

Визначити масу води яка утвориться при взаємодії 4 моль сульфатної кислоти з натрійом гідроксидом​

Answer 1

H2SO4 + 2NaOH = Na2SO4 + H2O

μ(H2SO4) = 4 моль

m(H2O) - ?

Решение:

1) μ(H2SO4) = μ(H2O) = 4 моль

2) m(H2O) = 4 моль * 18 г/моль = 72 г

Ответ: 72 г

Answer 2

Calculating the Mass of Water Formed from the Reaction of 4 Moles of Sulfuric Acid with Sodium Hydroxide

To determine the mass of water formed from the reaction of 4 moles of sulfuric acid with sodium hydroxide, we can use the balanced chemical equation for the reaction between sulfuric acid (H2SO4) and sodium hydroxide (NaOH).

The balanced chemical equation for the reaction is: H2SO4 + 2NaOH → Na2SO4 + 2H2O

From the balanced chemical equation, we can see that 1 mole of sulfuric acid reacts with 2 moles of sodium hydroxide to produce 2 moles of water.

Calculation:

Given: 4 moles of sulfuric acid (H2SO4)

Using the stoichiometry of the balanced chemical equation, we can calculate the moles of water produced: Moles of water = 2 moles of water per 1 mole of sulfuric acid * 4 moles of sulfuric acid Moles of water = 8 moles

Now, to find the mass of water formed, we can use the molar mass of water, which is approximately 18.01528 grams/mol.

Mass of water = Moles of water * Molar mass of water Mass of water = 8 moles * 18.01528 g/mol Mass of water ≈ 144.12224 grams

Therefore, the mass of water formed when 4 moles of sulfuric acid react with sodium hydroxide is approximately 144.12224 grams.