Question

Дам 40 балов!!!!!!!!! Необхідно одержати сульфатну кислоту кількістю речовини 2 моль. Обчисли масу води та кількість речовини відповідного оксиду, які повинні прореагувати.​

Answer 1

Дано:

n(H2SO4)= 2 моль

Найти:

m(H2O)- ?

n(SO3)-?

Решение:

SO3+H2O=H2SO4

n(H2SO4)= n(SO3) =2 моль

n(H2SO4)=n(H2O)= 2 моль

m(H2O)=n*M = 2 моль*18 г/моль= 36 г

M(H2O) 1*2+16 =18 г/моль

Ответ: m(H2O)= 36 г; n(SO3)= 2 моль

Answer 2

Calculation of Water Mass and Amount of Reacting Oxide

To calculate the mass of water and the amount of reacting oxide needed to obtain 2 moles of sulfuric acid, we need to consider the balanced chemical equation for the reaction.

The balanced chemical equation for the reaction between water and sulfur trioxide (SO3) to form sulfuric acid (H2SO4) is:

SO3 + H2O → H2SO4

From the equation, we can see that 1 mole of SO3 reacts with 1 mole of H2O to produce 1 mole of H2SO4.

Given that we want to obtain 2 moles of sulfuric acid, we can conclude that we need 2 moles of SO3 and 2 moles of H2O for the reaction.

To calculate the mass of water, we need to know the molar mass of water, which is approximately 18.015 g/mol.

The mass of water can be calculated using the formula:

Mass of water = Number of moles of water × Molar mass of water

Substituting the values, we get:

Mass of water = 2 moles × 18.015 g/mol = 36.03 g

Therefore, the mass of water required to obtain 2 moles of sulfuric acid is 36.03 grams.

To calculate the amount of reacting oxide, we can use the same approach. Since 1 mole of SO3 reacts with 1 mole of H2O, we need 2 moles of SO3 for the reaction.

Therefore, the amount of reacting oxide (SO3) needed is 2 moles.

In summary: - The mass of water required is 36.03 grams. - The amount of reacting oxide (SO3) needed is 2 moles.

Please note that the sources provided do not directly address the specific question. However, the information provided is based on the balanced chemical equation and the molar masses of water and sulfuric acid.