Question

Обчисліть масу хлоридної кислоти HCl, яка необхідна для нейтралізації 20 натрій гідрооксиду

Answer 1

NaOH + HCl = NaCl + H2O

m(NaOH) = 20 г

m(HCl) - ?

Решение:

1) μ(NaOH) = μ(HCl) = 20 г / 40 г/моль = 0,5 моль

2) m(HCl) = 0,5 моль * 36,5 г/моль = 18,25 г

Ответ: 18,25 г

Answer 2

Calculating the Amount of Hydrochloric Acid (HCl) Needed to Neutralize 20g of Sodium Hydroxide (NaOH)

To calculate the amount of hydrochloric acid (HCl) needed to neutralize 20g of sodium hydroxide (NaOH), we can use the balanced chemical equation for the neutralization reaction between HCl and NaOH:

HCl + NaOH → NaCl + H2O

From the balanced equation, we can see that the molar ratio of HCl to NaOH is 1:1. This means that 1 mole of HCl reacts with 1 mole of NaOH.

Now, let's calculate the amount of HCl needed to neutralize 20g of NaOH.

Step 1: Convert Sodium Hydroxide (NaOH) to Moles

The molar mass of NaOH is 40g/mol (sodium (Na) has a molar mass of 23g/mol, oxygen (O) has a molar mass of 16g/mol, and hydrogen (H) has a molar mass of 1g/mol).

Using the formula: moles = mass / molar mass

We can calculate the moles of NaOH: moles = 20g / 40g/mol = 0.5 moles

Step 2: Calculate the Amount of Hydrochloric Acid (HCl) Needed

Since the molar ratio of HCl to NaOH is 1:1, the amount of HCl needed will be the same as the amount of NaOH in moles.

Therefore, the amount of HCl needed to neutralize 20g of NaOH is also 0.5 moles.

Step 3: Convert Moles of HCl to Grams

The molar mass of HCl is 36.5g/mol (hydrogen (H) has a molar mass of 1g/mol, and chlorine (Cl) has a molar mass of 35.5g/mol).

Using the formula: mass = moles × molar mass

We can calculate the mass of HCl needed: mass = 0.5 moles × 36.5g/mol = 18.25g

Therefore, the mass of hydrochloric acid (HCl) needed to neutralize 20g of sodium hydroxide (NaOH) is 18.25 grams.