Question

M(CaCl2)-? v(NH3)-? ------------------- m(Ca(OH)2)=148г уравнение:Ca(OH)2+2NH4Cl=CaCl2+2NH3+2H2O​

Answer 1

Ответ : m (CaCl2) = 222 г
v (NH3) = 4 моль

Решение на фото

Answer 2

I can chat with you in Russian. You asked me to answer in detail. You want to find the mass of CaCl2 and the volume of NH3 in a chemical reaction. You gave me the mass of Ca(OH)2 and the equation. Here is how I solved it:

First, I calculated the molar mass of Ca(OH)2 using the atomic masses of the elements. I found that it is 74 g/mol. Then, I used the mass of Ca(OH)2 to find the number of moles of Ca(OH)2. I divided 148 g by 74 g/mol and got 2 mol.

Next, I used the mole ratio of Ca(OH)2 and CaCl2 from the equation. For every one mole of Ca(OH)2, there is one mole of CaCl2. So, the number of moles of CaCl2 is also 2 mol. Then, I calculated the molar mass of CaCl2 using the atomic masses of the elements. I found that it is 111 g/mol. Finally, I used the number of moles and the molar mass of CaCl2 to find the mass of CaCl2. I multiplied 2 mol by 111 g/mol and got 222 g.

Similarly, I used the mole ratio of Ca(OH)2 and NH3 from the equation. For every one mole of Ca(OH)2, there are two moles of NH3. So, the number of moles of NH3 is 4 mol. Then, I used the ideal gas law to find the volume of NH3 at standard temperature and pressure (STP). I assumed that the pressure is 1 atm and the temperature is 273 K. I also used the gas constant R as 0.0821 L*atm/(mol*K). I rearranged the ideal gas law as V = n*R*T/P and plugged in the values. I got 89.8 L.

Therefore, the mass of CaCl2 is 222 g and the volume of NH3 is 89.8 L. I hope this helps you understand the solution. If you have any other questions, feel free to ask me.Ответь+подробно.++M(CaCl2)-?+++v(NH3)-?+-------------------+m(Ca(OH)2)=148г+уравнение:Ca(OH)2+2NH4Cl=CaCl2+2NH3+2H2O​+