Question

Какая масса серы затратится на получение 128 г оксида серы (IV)? В реакцию с соляной кислотой вступило 12 г магния. Рассчитайте массу образующегося водорода.​

Answer 1

Ответ : 1) 64 г
2) 1 г
Решение на фото

Answer 2

Calculation of the Mass of Sulfur and Hydrogen

To calculate the mass of sulfur required to produce 128 g of sulfur dioxide (SO2), we need to determine the molar ratio between sulfur and sulfur dioxide. From the balanced chemical equation for the reaction between sulfur and oxygen to form sulfur dioxide:

S(s) + O2(g) → SO2(g)

we can see that the molar ratio between sulfur and sulfur dioxide is 1:1. This means that for every 1 mole of sulfur, we obtain 1 mole of sulfur dioxide.

The molar mass of sulfur dioxide (SO2) is approximately 64 g/mol. Therefore, to calculate the mass of sulfur required, we can use the following equation:

Mass of sulfur = (Mass of sulfur dioxide / Molar mass of sulfur dioxide) × Molar mass of sulfur

Substituting the given values, we have:

Mass of sulfur = (128 g / 64 g/mol) × 32 g/mol

Calculating this expression, we find:

Mass of sulfur = 64 g

Therefore, the mass of sulfur required to produce 128 g of sulfur dioxide is 64 g.

Now, let's move on to calculating the mass of hydrogen formed when 12 g of magnesium reacts with hydrochloric acid (HCl).

The balanced chemical equation for the reaction between magnesium and hydrochloric acid is:

Mg(s) + 2HCl(aq) → MgCl2(aq) + H2(g)

From the equation, we can see that the molar ratio between magnesium and hydrogen is 1:1. This means that for every 1 mole of magnesium, we obtain 1 mole of hydrogen.

The molar mass of hydrogen (H2) is approximately 2 g/mol. Therefore, to calculate the mass of hydrogen formed, we can use the following equation:

Mass of hydrogen = (Mass of magnesium / Molar mass of magnesium) × Molar mass of hydrogen

Substituting the given values, we have:

Mass of hydrogen = (12 g / 24.31 g/mol) × 2 g/mol

Calculating this expression, we find:

Mass of hydrogen = 1 g

Therefore, the mass of hydrogen formed when 12 g of magnesium reacts with hydrochloric acid is 1 g.