Question

3) Zn 3 (PO4)2 = Mr= ​

Answer 1

Ответ:

Объяснение:

Mr(Zn3(PO4)2) = 3Ar(Zn) + 2*(Ar(P) + 4Ar(O) = 3 * 65 + 2 * (31 + 4 * 16) = 385 г/моль ​

Answer 2

To calculate the molar mass of Zn3(PO4)2 (zinc phosphate), we need to determine the atomic masses of zinc (Zn), phosphorus (P), and oxygen (O), and then multiply them by their respective subscripts in the chemical formula.

The atomic mass of zinc (Zn) is approximately 65.38 g/mol. The atomic mass of phosphorus (P) is approximately 30.97 g/mol. The atomic mass of oxygen (O) is approximately 15.999 g/mol.

Now let's calculate the molar mass of Zn3(PO4)2:

Molar mass = (3 * atomic mass of Zn) + (2 * atomic mass of P) + (8 * atomic mass of O)

Molar mass = (3 * 65.38 g/mol) + (2 * 30.97 g/mol) + (8 * 15.999 g/mol)

Molar mass = 196.14 g/mol + 61.94 g/mol + 127.992 g/mol

Molar mass = 386.072 g/mol

Therefore, the molar mass of Zn3(PO4)2 (zinc phosphate) is approximately 386.072 g/mol.