Question

Li₂O + H₂O → ... - BaO +...→ BaCl +H_O CO₂+ KOH →... +... P2O5 +... H3PO4 ZnO + NaOH... + H₂O Fe₂O3 + HCl → ... + H₂O ->

Answer 1

H2O + Li2O → 2 LiOH

BaO + 2HCl → BaCl2 + H2O

CO2 + 2KOH → K2CO3 + H2O

P2O5 + 3H2O = 2H3PO4

ZnO + 2NaOH → Na2ZnO2 + H2O

Fe2O3 + 6HCl → 2FeCl3 + 3H2O

Answer 2

Let's go through each of the chemical equations you provided step by step:

1. Li₂O + H₂O → ? When lithium oxide (Li₂O) reacts with water (H₂O), it forms lithium hydroxide (LiOH).

The balanced equation is: Li₂O + H₂O → 2LiOH

2. BaO + ? → BaCl + H₂O In this equation, we need another reactant for barium oxide (BaO) to form barium chloride (BaCl₂) and water (H₂O). The missing reactant is hydrochloric acid (HCl).

The balanced equation is: BaO + 2HCl → BaCl₂ + H₂O

3. CO₂ + KOH → ? + ? When carbon dioxide (CO₂) reacts with potassium hydroxide (KOH), it forms potassium carbonate (K₂CO₃) and water (H₂O).

The balanced equation is: CO₂ + 2KOH → K₂CO₃ + H₂O

4. P₂O₅ + ? → H₃PO₄ To obtain phosphoric acid (H₃PO₄) from diphosphorus pentoxide (P₂O₅), we need water (H₂O).

The balanced equation is: P₂O₅ + 3H₂O → 2H₃PO₄

5. ZnO + NaOH + H₂O → ? When zinc oxide (ZnO) reacts with sodium hydroxide (NaOH) and water (H₂O), it forms sodium zincate (Na₂Zn(OH)₄).

The balanced equation is: ZnO + 2NaOH + H₂O → Na₂Zn(OH)₄

6. Fe₂O₃ + HCl → ? + H₂O When iron(III) oxide (Fe₂O₃) reacts with hydrochloric acid (HCl), it forms iron(III) chloride (FeCl₃) and water (H₂O).

The balanced equation is: Fe₂O₃ + 6HCl → 2FeCl₃ + 3H₂O