Question

C2h5oh-c2h4-c2h6-c2h5br-c2h4br2-c2h3br3

Answer 1

H2SO4
1. C2H5OH ————> C2H4 + H2O
2. C2H4 + H2 —-> C2H6
hv
3. C2H6 + Br2 —-> C2H5Br + HBr
hv
4.C2H5Br + Br2 —-> C2H4Br + HBr
hv
5. C2H4Br + Br2 —-> C2H3Br + HBr
P.s. Если не очень понятно, hv это аш ню, ну или свет, v пишется как ню письменная, то что я написала над стрелкой, так и должно быть над ней, это условие реакции

Answer 2

The series of compounds you have provided is a representation of the reaction pathway for the conversion of ethanol (C2H5OH) to bromoform (C2HBr3) via several intermediate compounds. Let's break down the reaction steps:

1. Ethanol (C2H5OH): Ethanol is a common alcohol used as a solvent and fuel. It consists of two carbon atoms (C2), five hydrogen atoms (H5), and one oxygen atom (O).

2. Ethene (C2H4): Ethene, also known as ethylene, is an unsaturated hydrocarbon. It is produced by removing a molecule of water from ethanol through a dehydration reaction. Ethene has two carbon atoms (C2) and four hydrogen atoms (H4).

3. Ethane (C2H6): Ethane is an alkane with two carbon atoms (C2) and six hydrogen atoms (H6). It is obtained by the addition of hydrogen to ethene through a hydrogenation reaction.

4. Ethyl bromide (C2H5Br): Ethyl bromide is formed by replacing one hydrogen atom in ethane with a bromine atom (Br). This substitution reaction is carried out using hydrogen bromide (HBr).

5. 1,2-Dibromoethane (C2H4Br2): In this step, one hydrogen atom in ethene is substituted by a bromine atom, resulting in 1,2-dibromoethane. The reaction is known as halogenation and requires the presence of a halogen, such as bromine (Br2).

6. Tribromomethane (C2HBr3): Finally, in the last step, the last hydrogen in 1,2-dibromoethane is replaced with a bromine atom to form tribromomethane, also called bromoform (C2HBr3).

Please note that the reactions mentioned here are simplified representations. In reality, there might be additional reactants, catalysts, or reaction conditions involved.