Question

C2H2 + Ag(NH3)2OH ＞X1+ HCl ＞X2 + H2O ＞CH3CHO + H2 ＞ X3 ＞ этилацетат

Answer 1

1. Взаимодействие с аммиачным раствором оксида серебра - качественная реакция на концевую тройную связь.

Все реакции на фото.

3. Взаимодействие алкинов с водой - реакция Кучерова - условия указаны над стрелкой - идет в кислой среде в присутствии соли ртути, как правило, это PbSO4 + H2SO4 - катализатор.

Answer 2

The chemical reactions you have provided involve several steps. Let's break down each step and identify the products formed:

Step 1: C2H2 + Ag(NH3)2OH → X1 + HCl In this step, acetylene (C2H2) reacts with silver ammine hydroxide (Ag(NH3)2OH) to form a compound X1 and hydrochloric acid (HCl).

Step 2: X1 + HCl → X2 + H2O Here, the compound X1 reacts with hydrochloric acid (HCl) to produce a new compound X2 and water (H2O).

Step 3: X2 + H2O → CH3CHO + H2 In this step, X2 reacts with water (H2O) to form acetaldehyde (CH3CHO) and hydrogen gas (H2).

Step 4: CH3CHO + H2 → X3 The acetaldehyde (CH3CHO) produced in the previous step undergoes a reaction to form a compound X3. The specific details of this reaction are not provided, so we cannot determine the exact products formed in this step.

Step 5: X3 → этилацетат (ethyl acetate) In the final step, the compound X3 undergoes a reaction to form ethyl acetate, which is represented as "этилацетат" in Russian.

Overall, the series of reactions results in the conversion of acetylene (C2H2) to ethyl acetate through several intermediate compounds.