Question

Mn(NO3)2 + PbO2 + HNO3 → HMnO4 + Pb(NO3)2 + H2O

Answer 1

5PbO2 + 2Mn(NO3)2+6HNO3 => 2H2O + 5Pb(NO3)2 + 2HMnO4  

 

Окисление: Mn(2+) + 4H2O - 5e(-) => MnO4(-) + 8H(+) - коэффициент 2- Mn(2+) - восстановитель  

Восстановление: PbO2+ 4H(+) + 2e(-) => Pb(2+) + 2H2O - коэффициент 5 - Pb(4-) в PbO2 - окислитель

Answer 2

This is a redox reaction where the manganese ion (Mn^2+) is being oxidized to form permanganate ion (HMnO4), while the lead ion (Pb^4+) is being reduced to form lead nitrate (Pb(NO3)2). The balanced chemical equation is:

2 Mn(NO3)2 + PbO2 + 4 HNO3 → 2 HMnO4 + Pb(NO3)2 + 2 H2O

In this equation, two molecules of Mn(NO3)2 react with one molecule of PbO2 and four molecules of HNO3 to produce two molecules of HMnO4, one molecule of Pb(NO3)2, and two molecules of H2O. The coefficients in front of the reactants and products ensure that the number of atoms of each element is balanced on both sides of the equation.