Question

рассчитайте относительную молекулярную массу: Al(No3)3, P2O5, No2, O2, K2Co3, Li3Po4​

Answer 1

Ответ:

Mr(Al(NO3)3) = 27 + 14×3 + (16×3)×3 = 213

Mr(P2O5) = 31×2 + 16×5 = 142

Mr(NO2) = 14 + 16×2 = 48

Mr(O2) = 16×2 = 32

Mr(K2CO3) = 39×2 + 12 + 16×3 = 138

Mr(Li3PO4) = 7×3 + 31 + 16×4 = 116

Answer 2

Al(NO3)3:
- M(Al) = 26.98 g/mol
- M(NO3) = 62.01 g/mol
- M(Al(NO3)3) = 26.98 + 3(62.01) = 208.01 g/mol

P2O5:
- M(P) = 30.97 g/mol
- M(O) = 15.99 g/mol
- M(P2O5) = 2(30.97) + 5(15.99) = 141.94 g/mol

NO2:
- M(N) = 14.01 g/mol
- M(O) = 15.99 g/mol
- M(NO2) = 14.01 + 2(15.99) = 46.00 g/mol

O2:
- M(O2) = 2(15.99) = 31.98 g/mol

K2CO3:
- M(K) = 39.10 g/mol
- M(C) = 12.01 g/mol
- M(O) = 15.99 g/mol
- M(K2CO3) = 2(39.10) + 12.01 + 3(15.99) = 138.21 g/mol

Li3PO4:
- M(Li) = 6.94 g/mol
- M(P) = 30.97 g/mol
- M(O) = 15.99 g/mol
- M(Li3PO4) = 3(6.94) + 30.97 + 4(15.99) = 115.79 g/mol