Question

CnH2n+2--->CnH2n+1 Br --->CnH2n+1 OH <---

Answer 1

очень интересная цепочка, впервые такую вижу

CnH2n+2 + Br2 -hv-> CnH2n+1Br + HBr

CnH2n+1Br + NAOH (водный) -> Cnh2n+1 OH +nabr

Объяснение:

первая формула алкана, прибавим бром, условием будет квант света, у нас получается (допустим возьмём этан) бромэтан, далее naoh водный и у нас получится этанол

Answer 2

This is a chemical reaction called "free radical halogenation" or "Halogenation of Alkanes". The reaction involves substitution of a halogen atom (typically chlorine or bromine) for a hydrogen atom in an alkane molecule. This creates a new compound with one fewer hydrogen and one more halogen atom.

The overall reaction can be represented as follows:

CnH2n+2 + X2 → CnH2n+1X + HX

where X is a halogen atom (either Cl or Br), and HX is the hydrogen halide (HCl or HBr) produced as a byproduct.

In the first step, a halogen molecule (X2) is split into two free radicals (X•). These free radicals then attack the alkane molecule, breaking one of its C-H bonds and forming a new C-X bond, while also creating a new C• free radical.

CnH2n+2 + X• → CnH2n+1• + HX

In the second step, the C• free radical reacts with another halogen molecule to form a new C-X bond and a new X• free radical, which can continue the chain reaction.

CnH2n+1• + X2 → CnH2n+1X + X•

Finally, a termination step occurs, in which two free radicals combine to form a stable compound.

C• + C• → C-C

This reaction can be used to prepare halogenated organic compounds, which have a wide range of applications in industry and medicine. For example, chlorinated hydrocarbons are used as solvents, refrigerants, and pesticides, while brominated compounds are used as flame retardants and in pharmaceuticals.