Question

Ch4-c2h2-c2h4-c2h5oh=c2h4=c2h4br2

Answer 1

CH4->C2H2->C2H4->C2H5OH->C2H4->C2H4Br2

2 CH4=C2H2+3 H2

C2H2+H2=C2H4

C2H4+H2O=C2H5OH

C2H5OH=C2H4+H2O

C2H4+Br2=C2H4Br2

Answer 2

The given equation appears to be a chemical reaction equation that describes the conversion of a mixture of four compounds, namely CH4 (methane), C2H2 (acetylene), C2H4 (ethylene), and C2H5OH (ethanol), into two compounds, C2H4 (ethylene) and C2H4Br2 (1,2-dibromoethane).

The equation is written as follows:

CH4 + C2H2 + C2H4 + C2H5OH → C2H4 + C2H4Br2

To balance this chemical equation, we need to make sure that the number of atoms of each element is equal on both sides of the equation. We can start by counting the number of atoms of each element in each compound:

On the left-hand side of the equation:

• CH4: 1 carbon atom, 4 hydrogen atoms
• C2H2: 2 carbon atoms, 2 hydrogen atoms
• C2H4: 2 carbon atoms, 4 hydrogen atoms
• C2H5OH: 2 carbon atoms, 6 hydrogen atoms, 1 oxygen atom

On the right-hand side of the equation:

• C2H4: 2 carbon atoms, 4 hydrogen atoms
• C2H4Br2: 2 carbon atoms, 4 hydrogen atoms, 2 bromine atoms

To balance the equation, we need to adjust the coefficients of the compounds so that the number of atoms of each element is the same on both sides. Here's one possible balanced equation:

CH4 + 2C2H2 + C2H4 + C2H5OH → 3C2H4 + C2H4Br2

Now, let's check that the equation is balanced by counting the number of atoms of each element on both sides:

On the left-hand side:

• 1 carbon atom: 1 from CH4, 2 from C2H2, 2 from C2H4, 2 from C2H5OH, for a total of 7
• 4 hydrogen atoms: 4 from CH4, 2 from C2H2, 4 from C2H4, 6 from C2H5OH, for a total of 16
• 1 oxygen atom: 1 from C2H5OH

On the right-hand side:

• 2 carbon atoms: 3 from C2H4, 2 from C2H4Br2, for a total of 5
• 4 hydrogen atoms: 3 from C2H4, 1 from C2H4Br2, for a total of 4
• 2 bromine atoms: 2 from C2H4Br2

We can see that the number of atoms of each element is the same on both sides, so the equation is balanced.