Question

KMn4+HCl->KCl+MnCl2+Cl2+H2O

Answer 1

пропущен кислород, смотри внимательно!

ст. ок. только тех, которые изменятся

KMn(+7)О4+HCl(-)->KCl+Mn(+2)Cl2+Cl(0)2+H2O

Mn(+7)+5е= Mn(+2) ок-ль, пр. вос-я

2Cl(-)-2е=Cl(0)2 в-ль, пр. ок-я

2KMnО4+8HCl->2KCl+2MnCl2+5Cl2+4H2O

Answer 2

4KMn4+8HCl => 4KCl+MnCl2+Cl2+4H2O

Answer 3

The balanced chemical equation for the reaction between KMnO4 and HCl is:

2KMnO4 + 16HCl → 2KCl + 2MnCl2 + 5Cl2 + 8H2O

In this reaction, potassium permanganate (KMnO4) reacts with hydrochloric acid (HCl) to form potassium chloride (KCl), manganese(II) chloride (MnCl2), chlorine gas (Cl2), and water (H2O).

It's important to note that this reaction is a redox reaction, where the KMnO4 is being reduced and the HCl is being oxidized. The manganese in the KMnO4 is being reduced from a +7 oxidation state to a +2 oxidation state, while the chlorine in the HCl is being oxidized from a -1 oxidation state to a 0 oxidation state in the form of Cl2.

To balance the equation, you need to make sure that the number of atoms of each element is the same on both sides of the equation. The balanced equation shows that two molecules of KMnO4 react with sixteen molecules of HCl to produce two molecules of KCl, two molecules of MnCl2, five molecules of Cl2, and eight molecules of H2O.