Question

2NaOH+Cl2=NaCl+NaClO+H2O. m=NaOH= 4,7 N(H2O)=?

Answer 1

2NaOh + Cl2 = NaClO + NaCl + h2o. ... 2NaOh + Cl2 = NaCl + NaClO + h2o.

Answer 2

To determine the number of moles of water (H2O) produced in the given reaction, we first need to balance the equation:

2 NaOH + Cl2 = NaCl + NaClO + H2O

The balanced equation shows that 2 moles of sodium hydroxide (NaOH) react with 1 mole of chlorine gas (Cl2) to produce 1 mole of sodium chloride (NaCl), 1 mole of sodium hypochlorite (NaClO), and 1 mole of water (H2O).

From the equation, we can see that the ratio of NaOH to H2O is 2:1. This means that for every 2 moles of NaOH used, 1 mole of H2O is produced.

Given that the number of moles of NaOH (m) is 4.7, we can calculate the number of moles of water (N(H2O)) produced using the ratio mentioned above:

N(H2O) = (m of NaOH) / 2 = 4.7 / 2 = 2.35 moles

Therefore, the number of moles of water (H2O) produced in the reaction is 2.35 moles.