
M*(H2SO4)=146г найти N и n


Ответы на вопрос

N=n*Na колво молекул=колво вещества*константу Авогадро
Na=6.02*10^23
У нас есть масса = 146 г
M(H2SO4)=1.01*2+32.06+4*16.00=98.08 г/моль
n=146:98.08=1.4885 моль - колво вещества
N=1.4885*6.02*10^23=8,96*10^23 -колво атомов)



To find the values of N (normality) and n (number of moles), we need additional information about the specific reaction being considered. Without that information, we can't determine the exact values of N and n.
In the given equation M*(H2SO4) = 146g, it seems like M is the molar mass of sulfuric acid (H2SO4) and 146g is the mass of the substance.
To find the number of moles (n), we can use the formula:
n = mass / molar mass
Assuming M represents the molar mass of H2SO4, we can calculate n as follows:
n = 146g / M
To find the normality (N), we need to know the specific reaction involved and the stoichiometry of the reaction. Normality is a measure of the concentration of a solution, and it depends on the number of equivalents of the solute in a given volume of solution. Without knowing the reaction and the specific conditions, we can't determine the normality (N).
Please provide more details about the reaction, including the balanced equation and any other relevant information, so that we can assist you further in finding the values of N and n.


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