Question

CuSO4+KL=K2SO4+CuL+L2 ОВР

Answer 1

2CuSO4 + 4KI = 2CuI + I2 + 2K2SO4
Cu(+2) + 1e =  Cu(+1) 
2I(-) - 2e =  I2(0) 

Answer 2

The chemical equation you provided appears to be incorrect. It doesn't follow the laws of conservation of mass and charge. In a balanced chemical equation, the number of atoms of each element on both sides of the equation should be the same, and the charges should also balance.

If you intended to write a reaction involving copper sulfate (CuSO4) and potassium iodide (KI), the correct equation would be:

CuSO4 + 2KI → K2SO4 + CuI2

In this reaction, copper sulfate reacts with potassium iodide to produce potassium sulfate and copper(II) iodide.

Please note that the subscripts in CuI2 represent the oxidation state of copper in the compound, where the roman numeral II indicates that copper is in the +2 oxidation state.

If you have a different reaction or any specific questions, please provide more information, and I'll be happy to assist you.