Question

AlCl3+NaOH= А1(ОН)3+НС1(ионное уравнение)= Al(OH)3+NaOH=

Answer 1

1) AlCl3 + 3NaOH = Al(OH)3 + 3NaCl

2) Al(OH)3 + 3HCl = AlCl3 + 3H2O
Al(OH)3 + 3H+ +3Cl- = Al3+ + 3Cl- + H2O
Al(OH)3 + 3H = Al3+ + H2O

3) Al(OH)3 + NaOH = Na[Al(OH)4]

Answer 2

To balance the ionic equation for the reaction AlCl3 + NaOH = Al(OH)3 + NaCl, we need to consider the charges and the number of atoms on each side.

The balanced ionic equation for the reaction is as follows:

Al3+ + 3OH- + 3Na+ + 3Cl- → Al(OH)3 + 3Na+ + 3Cl-

Simplifying the equation by removing the spectator ions (ions that appear on both sides of the equation) gives:

Al3+ + 3OH- → Al(OH)3

So, the final ionic equation for the reaction AlCl3 + NaOH = Al(OH)3 + NaCl is:

Al3+ + 3OH- → Al(OH)3