Question

M(N2) =60g m(O2)=60g m(NO)-?

Answer 1

Ответ:

60

Объяснение:

Взяли по одной молекуле)

Answer 2

Ответ:

112,5 г

Объяснение:

Answer 3

To determine the mass of nitrogen monoxide (NO) produced, we need to use the balanced chemical equation for the reaction between nitrogen gas (N2) and oxygen gas (O2) to form nitrogen monoxide.

The balanced equation is as follows:

2 N2 + O2 → 2 NO

From the balanced equation, we can see that two moles of nitrogen gas react with one mole of oxygen gas to produce two moles of nitrogen monoxide.

Given that the mass of nitrogen gas (N2) is 60g and the mass of oxygen gas (O2) is also 60g, we need to calculate the amount of each gas in moles to determine the limiting reagent.

The molar mass of N2 is 28 g/mol, so the moles of N2 can be calculated as follows:

moles of N2 = mass of N2 / molar mass of N2 moles of N2 = 60g / 28 g/mol moles of N2 ≈ 2.143 mol

Similarly, the molar mass of O2 is 32 g/mol, so the moles of O2 can be calculated as follows:

moles of O2 = mass of O2 / molar mass of O2 moles of O2 = 60g / 32 g/mol moles of O2 ≈ 1.875 mol

Based on the stoichiometry of the balanced equation, we can determine that 2 moles of N2 react with 1 mole of O2 to produce 2 moles of NO.

Since the moles of N2 (2.143 mol) are greater than the moles of O2 (1.875 mol), we can conclude that O2 is the limiting reagent. This means that the reaction will consume all of the O2 and leave some N2 unreacted.

Now, we can determine the moles of NO produced using the moles of O2 as a reference:

moles of NO = (moles of O2 / 1) * 2 moles of NO = 1.875 mol * 2 moles of NO ≈ 3.75 mol

Finally, we can calculate the mass of NO produced using the moles of NO and the molar mass of NO. The molar mass of NO is approximately 30 g/mol.

mass of NO = moles of NO * molar mass of NO mass of NO = 3.75 mol * 30 g/mol mass of NO ≈ 112.5 g

Therefore, approximately 112.5 grams of nitrogen monoxide (NO) would be produced in this reaction.