Вопрос задан 05.05.2019 в 07:39. Предмет Математика. Спрашивает Пинжина Полина.

В альбоме 36 страниц света изрисовала 4/9 всех страниц сколько страниц использовала света? от мотка

тесьмы отрезали 4/5 что составило 16 м сколько тесьмы было в рулоне? ширина спортзала 15 м и составляет 3/4 его длины сколько потребуется плинтуса чтобы прибить его по всему периметру зала? в парке посадили 135 елей и пихт из них 5/7 ели сколько пихт посадили в парке? длина комнаты 9 м а ширина составляет 2/3 её длины сколько нужно квадратных метров чтобы покрыть пол? пожайл.. с пояснением..
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Отвечает Ергазина Адина.
36:9×4=16(стр.)-изрисовала Света.
16:4×5=20(м)-темьмы было.
15:3×4=20(м)-длина спортзала. 15×20=300(м)-плинтуса потребуется. я не уверенна в этом ответе.
135:5×7=189(дер.)-было всего. 189-135=54(пих.)-посадили в парке.
9:3×2=6 (м)-ширина комнаты. 9×6=54(кв.м)
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Отвечает нейросеть ChatGpt. Будьте внимательны, ответы нейросети могут содержать ошибочные или выдуманные данные.

Calculation 1: Number of Pages Used by Sveta

In the album with 36 pages, Sveta has drawn 4/9 of all the pages. To find out how many pages Sveta used, we can multiply the total number of pages by the fraction representing the pages she drew.

The calculation can be done as follows:

Number of pages used by Sveta = Total number of pages x Fraction of pages drawn by Sveta

Number of pages used by Sveta = 36 x (4/9)

To simplify the calculation, we can divide both the numerator and denominator of the fraction by their greatest common divisor, which is 4 in this case:

Number of pages used by Sveta = 36 x (1/9) = 4

Therefore, Sveta used 4 pages in the album.

Calculation 2: Length of Ribbon in the Roll

From a roll of ribbon, a piece measuring 4/5 of the total length, which is 16 m, was cut. To find out the length of the ribbon in the roll, we can use the following calculation:

Length of ribbon in the roll = Length of cut piece x (1 / Fraction of cut piece)

Length of ribbon in the roll = 16 m x (1 / (4/5))

To simplify the calculation, we can multiply the numerator and denominator of the fraction by their common denominator, which is 5 in this case:

Length of ribbon in the roll = 16 m x (5/4) = 20 m

Therefore, the length of the ribbon in the roll was 20 meters.

Calculation 3: Length of Baseboard Needed for the Gym

The width of the gym is 15 m, and it represents 3/4 of its length. To find out how much baseboard is needed to cover the entire perimeter of the gym, we can use the following calculation:

Length of gym = Width of gym / (3/4)

Length of gym = 15 m / (3/4)

To simplify the calculation, we can multiply the numerator and denominator of the fraction by their common denominator, which is 4 in this case:

Length of gym = 15 m / (3/4) = 15 m x (4/3) = 20 m

The perimeter of the gym is calculated by multiplying the length and width by 2:

Perimeter of gym = 2 x (Length of gym + Width of gym)

Perimeter of gym = 2 x (20 m + 15 m) = 2 x 35 m = 70 m

Therefore, 70 meters of baseboard will be needed to cover the entire perimeter of the gym.

Calculation 4: Number of Fir Trees Planted in the Park

In the park, 135 spruce and fir trees were planted, and 5/7 of them are spruce trees. To find out how many fir trees were planted in the park, we can use the following calculation:

Number of fir trees = Total number of trees x (1 - Fraction of spruce trees)

Number of fir trees = 135 trees x (1 - 5/7)

To simplify the calculation, we can subtract the fraction from 1:

Number of fir trees = 135 trees x (2/7) = 30 trees

Therefore, 30 fir trees were planted in the park.

Calculation 5: Area of the Room

The length of the room is 9 m, and its width is 2/3 of its length. To find out the number of square meters needed to cover the floor, we can use the following calculation:

Area of the room = Length of the room x Width of the room

Area of the room = 9 m x (2/3)

To simplify the calculation, we can divide the numerator and denominator of the fraction by their greatest common divisor, which is 3 in this case:

Area of the room = 9 m x (2/3) = 6 m²

Therefore, 6 square meters of flooring will be needed to cover the floor of the room.

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