Question

1)х4+х3-8х2-9х-9= 0 2)(1/n2-n -1/n2+n):n-2/n2-1 Пожалуйста, помогите

Answer 1

Кажется так..........

Answer 2

1) To solve the equation 4x^3 - 8x^2 - 9x - 9 = 0, we can use various methods such as factoring, the quadratic formula, or synthetic division. Let's use factoring in this case.

First, let's group the terms: (4x^3 - 8x^2) - (9x + 9) = 0

Now, let's factor out the common terms from each group: 4x^2(x - 2) - 9(x + 1) = 0

Now, we have two separate factors: 4x^2(x - 2) = 9(x + 1)

To solve for x, we can set each factor equal to zero: 4x^2 = 0 or x - 2 = 0 or 9(x + 1) = 0

Solving each equation separately: - From 4x^2 = 0, we find that x = 0. - From x - 2 = 0, we find that x = 2. - From 9(x + 1) = 0, we find that x = -1.

Therefore, the solutions to the equation 4x^3 - 8x^2 - 9x - 9 = 0 are x = 0, x = 2, and x = -1.

2) To simplify the expression (1/n^2 - n) - (1/n^2 + n) : n - 2/n^2 - 1, we can follow the order of operations (PEMDAS/BODMAS) and simplify step by step.

Let's break down the expression into smaller parts: (1/n^2 - n) - (1/n^2 + n) : n - 2/n^2 - 1

First, let's simplify the terms inside the parentheses: (1/n^2 - n) - (1/n^2 + n) : n - 2/n^2 - 1 = (1/n^2 - n) - (1/n^2 + n) : (n - 2/n^2 - 1)

Next, let's simplify the subtraction inside the parentheses: = (1/n^2 - n - 1/n^2 - n) : (n - 2/n^2 - 1) = (-2n) : (n - 2/n^2 - 1)

Now, let's simplify the division: = -2n / (n - 2/n^2 - 1)

At this point, we can't simplify the expression any further without knowing the specific values of n. The expression remains as -2n / (n - 2/n^2 - 1).

Please provide a specific value for n if you would like further simplification or evaluation of the expression.