Question

Из пункта А и Б Одновременно навстречу друг другу выехал велосипедист и мотоциклист скорость велосипедиста в 4 раза меньше скорости мотоциклиста через сколько минут велосипедист встретится если на путь от A до B мотоциклисту требуется 20 минут

Answer 1

Примем расстояние за 1
1/20 расстояния в минуту скорость мотоциклиста
1/20:4=1/80 велосипедиста
1/20+1/80=5/80=1/16 расстояния в минуту (скорость сближения)
1:1/16=16 минут встретятся

Answer 2

Problem Analysis

We are given that a cyclist and a motorcyclist start simultaneously from points A and B, respectively, and are moving towards each other. The speed of the cyclist is 4 times slower than the speed of the motorcyclist. We need to determine how many minutes it will take for the cyclist to meet the motorcyclist if the motorcyclist takes 20 minutes to travel from A to B.

Solution

Let's assume the distance between points A and B is d.

The speed of the cyclist is 4 times slower than the speed of the motorcyclist. Let's denote the speed of the motorcyclist as v. Therefore, the speed of the cyclist is v/4.

We can use the formula distance = speed × time to find the time it takes for the cyclist to travel from A to B.

For the motorcyclist: d = v × (20/60) (since the motorcyclist takes 20 minutes to travel from A to B)

For the cyclist: d = (v/4) × t (where t is the time taken by the cyclist to travel from A to B)

Since both the cyclist and the motorcyclist are moving towards each other, the sum of their distances traveled should be equal to the total distance between A and B.

Therefore, we can write the equation: d + d = v × (20/60) + (v/4) × t

Simplifying the equation: 2d = (v/3) + (v/4) × t

Now, we can solve for t.

Calculation

Let's substitute the