Вопрос задан 08.06.2023 в 23:30. Предмет Математика. Спрашивает Бугаёв Сергей.

814. 1) 12a - 1= -a + 25; (3) 8 + 3b = -7 + 2b; 5) 3y – 3 = 5 – y; 815. 1) 2x + 3 = x - 6; bפ​

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Отвечает Корниенко Ростислав.

Ответ:

814.

12a-1= -a+25

12a+a=25+1

13a=26

a=26:13

a= 2

815.

2x+3= x-6

2x-x= -6-3

2x-x= -9

x= -9

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Отвечает нейросеть ChatGpt. Будьте внимательны, ответы нейросети могут содержать ошибочные или выдуманные данные.

It seems like you have provided a list of equations. Let's go through them one by one:

Equation 814.1: 12a - 1 = -a + 25

To solve this equation, we need to isolate the variable "a" on one side of the equation. Let's begin by getting rid of the "-a" term by adding "a" to both sides:

12a + a - 1 = -a + a + 25 13a - 1 = 25

Next, let's isolate the term with "a" by adding 1 to both sides:

13a - 1 + 1 = 25 + 1 13a = 26

Finally, divide both sides by 13 to solve for "a":

a = 26/13 a = 2

So the solution to equation 814.1 is a = 2.

Equation 814.3: 8 + 3b = -7 + 2b

To solve this equation, let's isolate the term with "b" on one side. We can do this by subtracting 2b from both sides:

8 + 3b - 2b = -7 + 2b - 2b 8 + b = -7

Next, let's isolate the "b" term by subtracting 8 from both sides:

8 + b - 8 = -7 - 8 b = -15

So the solution to equation 814.3 is b = -15.

Equation 814.5: 3y - 3 = 5 - y

To solve this equation, let's begin by adding y to both sides to eliminate the "-y" term:

3y + y - 3 = 5 - y + y 4y - 3 = 5

Next, let's isolate the "y" term by adding 3 to both sides:

4y - 3 + 3 = 5 + 3 4y = 8

Finally, divide both sides by 4 to solve for "y":

y = 8/4 y = 2

So the solution to equation 814.5 is y = 2.

Equation 815.1: 2x + 3 = x - 6

To solve this equation, let's isolate the term with "x" on one side. We can do this by subtracting x from both sides:

2x - x + 3 = x - x - 6 x + 3 = -6

Next, let's isolate the "x" term by subtracting 3 from both sides:

x + 3 - 3 = -6 - 3 x = -9

So the solution to equation 815.1 is x = -9.

Please note that equation 815.b is incomplete. If you provide the complete equation, I'll be happy to help you solve it.

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