Question

(a+b)+(a+с)+(a+d)+(b+c)+(b+d)+(c+d) мұндағы a+b+c+d=1.5

Answer 1

(a+b)+(a+с)+(a+d)+(b+c)+(b+d)+(c+d) = 
= a+b+a+с+a+d+b+c+b+d+с+d = 
= 3а + 3b + 3c + 3d = 3 * (a + b + c + d).

если  a + b + c + d = 1,5:  3 * 1,5 = 4,5

Answer 2

Given that:

(a+b)+(a+c)+(a+d)+(b+c)+(b+d)+(c+d)

We can simplify this expression by grouping the terms with common variables:

a + a + a + b + b + c + c + d + d

Simplifying further, we get:

3a + 2b + 2c + 2d

Now, we know that a + b + c + d = 1.5, so we can substitute this into the expression above:

3(1.5) + 2b + 2c + 2d

4.5 + 2(b + c + d)

We can see that we cannot determine the value of (b + c + d) from the given information. However, we do know that a + b + c + d = 1.5, so we can say:

(b + c + d) = 1.5 - a

Substituting this into the expression we simplified earlier, we get:

4.5 + 2(1.5 - a)

Simplifying, we get:

7.5 - 2a

Therefore, the expression (a+b)+(a+c)+(a+d)+(b+c)+(b+d)+(c+d) simplifies to 7.5 - 2a, where a + b + c + d = 1.5.