Question

7(y+3)-2(y+2)=2(5y+1) решэния

Answer 1

7y+21-2y-4=10y+2
5y-10y=2+4-21
-5y=-15
y=-15/(-5)
y=3

Answer 2

7у+21-2у=10у+2
7у-2у-10у= -21+2
-5у=-19
у=3,8

Answer 3

Let's simplify the left-hand side of the equation first:

7(y+3) - 2(y+2) = 7y + 21 - 2y - 4 = 5y + 17

Now let's simplify the right-hand side of the equation:

2(5y+1) = 10y + 2

So the equation becomes:

5y + 17 = 10y + 2

Let's isolate the variable y on one side of the equation by subtracting 5y from both sides:

17 = 5y + 2

Subtracting 2 from both sides:

15 = 5y

Dividing both sides by 5:

y = 3

Therefore, the solution to the equation 7(y+3)-2(y+2)=2(5y+1) is y=3.