Question

(х+2)² = (1-х)².......................​

Answer 1

(х+2)² = (1-х)²

х²+4х+4=1-2х+х²

х²+4х+2х-х²=1-4

6х=-3

х=-0,5

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Answer 2

To solve the equation $(x + 2)^2 = (1 - x)^2$, you can follow these steps:

1. Expand both sides of the equation: $(x + 2)^2 = (1 - x)^2$ $(x + 2)(x + 2) = (1 - x)(1 - x)$

2. Simplify each side by multiplying the expressions: $(x^2 + 4x + 4) = (1 - 2x + x^2)$

3. Rearrange the terms so that all the terms are on one side of the equation: $x^2 + 4x + 4 - (1 - 2x + x^2) = 0$

4. Simplify and combine like terms: $x^2 + 4x + 4 - 1 + 2x - x^2 = 0$

5. Continue simplifying: $4x + 3 = 0$

6. Subtract 3 from both sides of the equation to isolate the term with x: $4x = -3$

7. Finally, divide both sides by 4 to solve for x: $x = \frac{-3}{4}$

So, the solution to the equation $(x + 2)^2 = (1 - x)^2$ is $x = \frac{-3}{4}$.