Question

в компьютере часто каждый символ кодируется 8 битами. статья,набранная на компьютере содержит 10 страниц на каждой странице 32 строки в каждой строке 64 символа.определите информационный обьем статьи в Кбайтах

Answer 1

10*32*64=20480, а 8 бит=1байт, то выходит что 20480:8=2560байт, а в Кбайтах 2560:1000=2,56 Кбайт

Answer 2

To determine the information volume of the article in kilobytes (KB), we need to calculate the total number of bits and then convert it to kilobytes.

Given:

• Each character is encoded using 8 bits (1 byte).
• There are 10 pages, each with 32 lines.
• Each line contains 64 characters.

First, let's calculate the number of characters in the article: Number of characters per page = 32 lines * 64 characters per line = 2048 characters Total number of characters in the article = 10 pages * 2048 characters per page = 20,480 characters

Next, calculate the number of bits: Number of bits per character = 8 bits Total number of bits in the article = 20,480 characters * 8 bits per character

Now, convert the total number of bits to kilobytes: 1 Kilobyte (KB) = 1024 bytes 1 byte = 8 bits

Total information volume in kilobytes (KB) = (Total number of bits) / (8 bits per byte * 1024 bytes per kilobyte)

Let's do the math:

Total information volume in bits = 20,480 characters * 8 bits per character = 163,840 bits

Total information volume in kilobytes (KB) = 163,840 bits / (8 bits per byte * 1024 bytes per kilobyte) Total information volume in kilobytes (KB) ≈ 20 KB

So, the information volume of the article is approximately 20 kilobytes.