Question

Осуществите цепочки превращений: 1)Mg - MgO - MgCl2 - MgOH2 - MgO 2)C - Co2 - Na2Co3 - Na2So4 - BaSo4. 3) Какая масса сульфата бария образуется при взаимодействии 30,6 г оксида бария с достаточным кол-вом серной кислоты ?

Answer 1

Chain of Transformations:

1) Mg -> MgO -> MgCl2 -> MgOH2 -> MgO

2) C -> Co2 -> Na2Co3 -> Na2So4 -> BaSo4

Mass of Barium Sulfate Formed:

To determine the mass of barium sulfate formed when 30.6 g of barium oxide reacts with an excess of sulfuric acid, we need to know the balanced chemical equation for the reaction. Unfortunately, the search results did not provide the specific balanced equation for this reaction. However, we can still provide some general information about the calculation.

The balanced equation will allow us to determine the stoichiometric ratio between barium oxide and barium sulfate. From this ratio, we can calculate the mass of barium sulfate formed.

Here is a general outline of the calculation:

1. Write the balanced equation for the reaction between barium oxide and sulfuric acid. 2. Determine the stoichiometric ratio between barium oxide and barium sulfate. 3. Use the stoichiometric ratio to calculate the moles of barium sulfate formed. 4. Convert the moles of barium sulfate to grams using the molar mass of barium sulfate.

Unfortunately, without the specific balanced equation, we cannot provide an exact answer to the question. It is recommended to consult a chemistry textbook or reliable source to obtain the balanced equation and perform the calculation.

Please let me know if there is anything else I can help you with.