Question

При взаимодействии 130г цинка с соляной кислотой было получено 33.6 водорода. Каков выход водорода от теоретически возможного? написать реакцию

Answer 1

Calculation of Hydrogen Yield

To calculate the theoretical yield of hydrogen gas produced when 130g of zinc reacts with hydrochloric acid, we need to consider the balanced chemical equation for the reaction. The balanced equation is as follows:

Zn + 2HCl → ZnCl2 + H2

From the equation, we can see that 1 mole of zinc reacts with 2 moles of hydrochloric acid to produce 1 mole of hydrogen gas. The molar mass of zinc (Zn) is approximately 65.38 g/mol.

To calculate the moles of zinc used, we divide the mass of zinc (130g) by its molar mass:

Moles of Zn = Mass of Zn / Molar mass of Zn = 130g / 65.38 g/mol = 1.988 mol

According to the stoichiometry of the balanced equation, 1 mole of zinc reacts to produce 1 mole of hydrogen gas. Therefore, the moles of hydrogen gas produced will be equal to the moles of zinc used:

Moles of H2 = Moles of Zn = 1.988 mol

Since 1 mole of any gas occupies 22.4 liters at standard temperature and pressure (STP), we can calculate the volume of hydrogen gas produced:

Volume of H2 = Moles of H2 * Molar volume at STP = 1.988 mol * 22.4 L/mol = 44.5 L

Therefore, the theoretical yield of hydrogen gas produced when 130g of zinc reacts with hydrochloric acid is 44.5 liters.

Balanced Chemical Equation

The balanced chemical equation for the reaction between zinc and hydrochloric acid is:

Zn + 2HCl → ZnCl2 + H2

Where: - Zn represents zinc - HCl represents hydrochloric acid - ZnCl2 represents zinc chloride - H2 represents hydrogen gas