Question

С помощью раствора серной кислоты можно определить наличие в растворе: а) хлорида меди (II) б) нитрата магния Напишите молекулярное и сокращенное ионно-молекулярное уравнения протекающей реакции

Answer 1

Ba(NO3)2 + H2SO4 = BaSO4 + 2HNO3
                                     осадок
Ba(2+) + SO4(2-) = BaSO4

ответ г

Answer 2

Determining the Presence of Copper (II) Chloride and Magnesium Nitrate Using Sulfuric Acid

To determine the presence of copper (II) chloride and magnesium nitrate in a solution, sulfuric acid can be used. The reaction between sulfuric acid and these compounds can be represented by the following molecular, condensed, and ion-molecular equations:

1. Molecular Equation: - Copper (II) Chloride: H2SO4 + CuCl2 → CuSO4 + 2HCl - Magnesium Nitrate: H2SO4 + Mg(NO3)2 → MgSO4 + 2HNO3

2. Condensed Equation: - Copper (II) Chloride: H2SO4 + CuCl2 → CuSO4 + HCl - Magnesium Nitrate: H2SO4 + Mg(NO3)2 → MgSO4 + HNO3

3. Ion-Molecular Equation: - Copper (II) Chloride: 2H+ + SO4^2- + Cu^2+ + 2Cl^- → CuSO4 + 2H+ + 2Cl^- - Magnesium Nitrate: 2H+ + SO4^2- + Mg^2+ + 2NO3^- → MgSO4 + 2H+ + 2NO3^-

Please note that the above equations represent the reaction between sulfuric acid and copper (II) chloride or magnesium nitrate. The resulting products are copper (II) sulfate, hydrochloric acid, magnesium sulfate, and nitric acid.

It's important to mention that these equations are based on the information provided in the search snippets.

If you have any further questions, feel free to ask!