Вопрос задан 16.01.2020 в 09:34. Предмет Химия. Спрашивает Мартыненко Самира.

Дано: P2O5 P2O3 Найти: W1 (P)? W2(P) ?

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Отвечает Грама Ростислав.

P2O5 - оксид фосфора (V)

Mr (P2O5) = 31 * 2 + 16 * 5 = 62 + 80 = 142

W (P) = 62 / 142 * 100 = 43.66 %

P2O3 - оксид фосфора (III)

Mr (P2O3) = 31 * 2 + 16 * 3 = 62 + 48 = 110

W (P) = 62 / 110 * 100 = 56.36 %


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Отвечает нейросеть ChatGpt. Будьте внимательны, ответы нейросети могут содержать ошибочные или выдуманные данные.

Problem Analysis

The problem provides the chemical compounds P2O5 and P2O3 and asks for the weights W1 and W2 of the elements P in these compounds.

Solution

To find the weights W1 and W2 of the element P in the compounds P2O5 and P2O3, we need to calculate the molar masses of P2O5 and P2O3 and then determine the weights of P based on their chemical formulas.

Calculation of Molar Mass

The molar mass of a compound is the sum of the atomic masses of all the atoms in the compound. To calculate the molar mass of P2O5 and P2O3, we need to know the atomic masses of P and O.

According to the periodic table, the atomic mass of P is approximately 31.0 g/mol, and the atomic mass of O is approximately 16.0 g/mol.

Using these atomic masses, we can calculate the molar masses of P2O5 and P2O3 as follows:

- Molar mass of P2O5 = (2 * atomic mass of P) + (5 * atomic mass of O) - Molar mass of P2O3 = (2 * atomic mass of P) + (3 * atomic mass of O)

Let's calculate the molar masses:

- Molar mass of P2O5 = (2 * 31.0 g/mol) + (5 * 16.0 g/mol) - Molar mass of P2O3 = (2 * 31.0 g/mol) + (3 * 16.0 g/mol)

Calculation of Weights

Now that we have the molar masses of P2O5 and P2O3, we can calculate the weights W1 and W2 of the element P in these compounds.

The weight of an element in a compound is calculated using the formula:

- Weight of element = (Number of atoms of the element) * (Atomic mass of the element)

In P2O5, there are 2 atoms of P, so the weight of P in P2O5 is:

- W1 = 2 * (Atomic mass of P)

In P2O3, there are 2 atoms of P, so the weight of P in P2O3 is:

- W2 = 2 * (Atomic mass of P)

Let's substitute the values of the atomic mass of P and calculate W1 and W2.

Calculation

- Atomic mass of P = 31.0 g/mol - Atomic mass of O = 16.0 g/mol

- Molar mass of P2O5 = (2 * 31.0 g/mol) + (5 * 16.0 g/mol) - Molar mass of P2O3 = (2 * 31.0 g/mol) + (3 * 16.0 g/mol)

- W1 = 2 * (31.0 g/mol) - W2 = 2 * (31.0 g/mol)

Let's calculate the values:

- Molar mass of P2O5 = (2 * 31.0 g/mol) + (5 * 16.0 g/mol) = 142.0 g/mol - Molar mass of P2O3 = (2 * 31.0 g/mol) + (3 * 16.0 g/mol) = 109.0 g/mol

- W1 = 2 * (31.0 g/mol) = 62.0 g - W2 = 2 * (31.0 g/mol) = 62.0 g

Answer

The weight W1 of the element P in the compound P2O5 is 62.0 g, and the weight W2 of the element P in the compound P2O3 is 62.0 g.

Please let me know if I can help you with anything else.

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