Question

Уравняйте реакцию с помощью электронного баланса. NA2 + KMnO4 + H2O --> S + MnO2 + NaOH + KOH

Answer 1

Сложно .Сейчас попробую

Answer 2

Balancing the Equation: Na2 + KMnO4 + H2O -> S + MnO2 + NaOH + KOH

To balance the given chemical equation: Na2 + KMnO4 + H2O -> S + MnO2 + NaOH + KOH, we need to ensure that the number of atoms of each element is the same on both sides of the equation.

Let's break down the equation and balance it step by step:

1. Start by balancing the atoms that appear in only one compound on each side of the equation. In this case, we have: - Sodium (Na): 2 Na on the left side and 1 Na on the right side. - Potassium (K): 1 K on the left side and 1 K on the right side. - Manganese (Mn): 1 Mn on the left side and 1 Mn on the right side. - Oxygen (O): 4 O in KMnO4 on the left side and 2 O in MnO2 on the right side.

2. Balance the atoms that appear in multiple compounds. In this case, we have: - Hydrogen (H): 2 H in H2O on the left side and 1 H in NaOH on the right side. To balance the hydrogen atoms, we can add a coefficient of 2 in front of NaOH, resulting in 2 NaOH. - Sulfur (S): 1 S on the right side. To balance the sulfur atom, we can add a coefficient of 2 in front of Na2, resulting in 2 Na2.

After balancing the equation, we have:

2 Na2 + KMnO4 + 2 H2O -> 2 S + MnO2 + 2 NaOH + KOH

This balanced equation ensures that the number of atoms of each element is the same on both sides.

Please note that the coefficients in front of the compounds represent the number of moles or molecules, not the charge of the ions.