Question

Обчисліть об‘єм водню який необхідний для відновлення Al з оксиду Al, що утворився під час розкладу 30 грам алюмінію гідроксиду. ПОМОГИТЕ ПОЖАЛУЙСТА! СРОЧНО!

Answer 1

2Al(OH)3=Al2O3+3H2O

n(Al(OH)3)=30г/78 г/моль= 0,385 моль

По УХР Al2O3 в два раза меньше, т.е. n(Al2O3)=0,1925 моль

Al2O3+3H2=2Al+3H2O

По УХР Н2 в три раза больше, т.е. n(H2)=0,1925*3=0,6 моль

V(H2)=0,6 моль*22,4 моль/л=13,44 л

Answer 2

Calculation of the Volume of Hydrogen Required to Reduce Aluminum Oxide

To calculate the volume of hydrogen required to reduce aluminum oxide, we need to consider the balanced chemical equation for the reaction. The reaction between aluminum oxide (Al2O3) and hydrogen gas (H2) produces aluminum (Al) and water (H2O). The balanced equation for this reaction is:

2 Al2O3 + 3 H2 → 4 Al + 3 H2O

From the balanced equation, we can see that 2 moles of aluminum oxide react with 3 moles of hydrogen gas to produce 4 moles of aluminum and 3 moles of water.

To determine the volume of hydrogen gas required, we need to convert the mass of aluminum hydroxide to moles and then use the mole ratio from the balanced equation.

Calculation Steps:

1. Convert the mass of aluminum hydroxide to moles. - The molar mass of aluminum hydroxide (Al(OH)3) is 78.0 g/mol. - Given that the mass of aluminum hydroxide is 30 g, we can calculate the number of moles using the formula:

moles = mass / molar mass

Substituting the values, we get:

moles = 30 g / 78.0 g/mol

Calculating this, we find that the number of moles of aluminum hydroxide is approximately 0.385 moles.

2. Use the mole ratio from the balanced equation to determine the moles of hydrogen gas required. - From the balanced equation, we know that 2 moles of aluminum oxide react with 3 moles of hydrogen gas. - Therefore, the mole ratio of aluminum oxide to hydrogen gas is 2:3.

Using this ratio, we can calculate the moles of hydrogen gas required:

moles of H2 = (moles of Al2O3) * (3 moles of H2 / 2 moles of Al2O3)

Substituting the value of moles of aluminum hydroxide (0.385 moles), we get:

moles of H2 = 0.385 moles * (3 moles of H2 / 2 moles of Al2O3)

Calculating this, we find that the moles of hydrogen gas required is approximately 0.5775 moles.

3. Convert the moles of hydrogen gas to volume. - To convert moles to volume, we need to use the ideal gas law, which states that:

PV = nRT

Where: - P is the pressure of the gas (in atm) - V is the volume of the gas (in liters) - n is the number of moles of the gas - R is the ideal gas constant (0.0821 L·atm/(mol·K)) - T is the temperature of the gas (in Kelvin)

- Since the pressure and temperature are not given in the question, we cannot calculate the exact volume of hydrogen gas required. However, we can provide an approximate value based on standard conditions.

At standard temperature and pressure (STP), the pressure is 1 atm and the temperature is 273 K.

Using these values, we can calculate the volume of hydrogen gas required:

V = (n * R * T) / P

Substituting the values, we get:

V = (0.5775 moles * 0.0821 L·atm/(mol·K) * 273 K) / 1 atm

Calculating this, we find that the volume of hydrogen gas required is approximately 12.7 liters.

Please note that this calculation assumes standard conditions (STP) and may not be accurate for non-standard conditions. Additionally, it is important to ensure safety precautions are followed when handling hydrogen gas, as it is highly flammable.