Question

Залізо масою 6.72 г спалили у 5 л хлору. Визначте масу хлориду Феруму, що утворився. А. 19,5 Г Б. 27,2 Г В. 12,8 Г Г. 19,0 Г Ответ обоснуйте пожалуйста

Answer 1

3Cl2 + 2Fe = 2FeCl3

x=325*6,72/112=19,5

Ответ: а)19,5г

 

 

 

 

 

 

Answer 2

Calculation of the Mass of Iron Chloride Formed

To determine the mass of iron chloride formed when 6.72 g of iron is burned in 5 L of chlorine gas, we need to consider the balanced chemical equation for the reaction between iron and chlorine. The balanced equation is as follows:

2 Fe + 3 Cl2 -> 2 FeCl3

From the balanced equation, we can see that 2 moles of iron react with 3 moles of chlorine gas to produce 2 moles of iron chloride.

To find the mass of iron chloride formed, we need to calculate the number of moles of iron used and then use the mole ratio from the balanced equation to determine the moles of iron chloride formed. Finally, we can convert the moles of iron chloride to grams using the molar mass of iron chloride.

Let's calculate the mass of iron chloride formed step by step:

Step 1: Calculate the number of moles of iron used. - Given mass of iron = 6.72 g - Molar mass of iron (Fe) = 55.845 g/mol (from the periodic table) - Number of moles of iron = mass of iron / molar mass of iron

Number of moles of iron = 6.72 g / 55.845 g/mol = 0.120 moles [[1]].

Step 2: Use the mole ratio from the balanced equation to determine the moles of iron chloride formed. - From the balanced equation, we can see that 2 moles of iron react to form 2 moles of iron chloride. - Therefore, the moles of iron chloride formed will be the same as the moles of iron used.

Moles of iron chloride formed = 0.120 moles.

Step 3: Convert the moles of iron chloride to grams using the molar mass of iron chloride. - Molar mass of iron chloride (FeCl3) = 162.204 g/mol (from the periodic table) - Mass of iron chloride formed = moles of iron chloride formed * molar mass of iron chloride

Mass of iron chloride formed = 0.120 moles * 162.204 g/mol = 19.464 g.

Therefore, the mass of iron chloride formed when 6.72 g of iron is burned in 5 L of chlorine gas is approximately 19.5 g (option A) [[1]].

Please note that the calculations provided are based on the given information and assumptions.