Question

4.коэффициент перед формулой оксида меди в уравнении CuO + H2=Cu+H2Oравена)1б)2в)3г)46.какие вещества образуются при взаимодействии оксида кальция с соляной кислотой а)H2б)H2Oв)CaSo4г)CaCl2​

Answer 1

Коэффициент равен 1

CaO + 2HCl=> H2O + CaCl2

Answer 2

I will answer your questions in detail.

4. The coefficient before the formula of copper oxide in the equation CuO + H2 = Cu + H2O is equal to

a) 1

b) 2

c) 3

d) 4

The correct answer is a) 1. This is because the equation is already balanced with one molecule of copper oxide and one molecule of hydrogen gas on the left side, and one atom of copper and one molecule of water on the right side. Therefore, no coefficient is needed before the formula of copper oxide.

6. What substances are formed when calcium oxide reacts with hydrochloric acid?

a) H2

b) H2O

c) CaSO4

d) CaCl2

The correct answer is b) H2O and d) CaCl2. This is because the reaction is a double displacement reaction, where the cations and anions of the reactants exchange places. The products are water and calcium chloride, which are both soluble in water. The balanced equation is:

CaO + 2HCl -> H2O + CaCl2

I hope this helps you understand the questions better.