Question

Рассчитайте степени окисления в следующих соединениях SF6

Answer 1

У серы +6 , у фтора -1

Answer 2

Calculation of Oxidation States in SF6

To calculate the oxidation states in SF6 (sulfur hexafluoride), we need to determine the oxidation state of each element in the compound.

SF6 consists of one sulfur atom (S) and six fluorine atoms (F). Fluorine is always assigned an oxidation state of -1 because it is the most electronegative element.

To find the oxidation state of sulfur (S), we can use the following equation:

Oxidation state of sulfur + (Oxidation state of fluorine x Number of fluorine atoms) = 0

Let's substitute the values:

Oxidation state of sulfur + (-1 x 6) = 0

Simplifying the equation:

Oxidation state of sulfur - 6 = 0

Adding 6 to both sides:

Oxidation state of sulfur = +6

Therefore, the oxidation state of sulfur in SF6 is +6.

Please note that this calculation is based on the assumption that the oxidation states of the other elements in the compound are known. In the case of SF6, fluorine has a fixed oxidation state of -1, so we can determine the oxidation state of sulfur using the equation mentioned above.