Question

Какой объём занимает 28г азота(N2)

Answer 1

M(N2) = 14 • 2 = 28 г/моль
n(N2) = 28 г : 28 г/моль = 1 моль
V(N2) = 22,4 л/моль • 1 моль = 22,4 л

Answer 2

Calculating the volume of 28g of nitrogen (N2)

The molar mass of nitrogen (N2) is 28.0134 g/mol. To calculate the volume occupied by 28g of nitrogen gas, we use the following steps:

1. Convert the mass to moles using the molar mass: 28g N2 / 28.0134 g/mol = 1 mol N2

2. Use the molar gas volume (22.4 L/mol at STP) to convert moles to volume: 1 mol N2 × 22.4 L/mol = 22.4 L

Therefore, the volume occupied by 28g of nitrogen gas at standard temperature and pressure (STP) is 22.4 L.

The key steps are: 1) Convert grams to moles using molar mass 2) Convert moles to liters using the molar gas volume

Let me know if you need any clarification or have additional questions!