Question

В стратосфере на высоте 20 – 30 км находится слой озона, формула которого О3 . Озон защищает Землю от мощного ультрафиолетового излучения. Найдите объём, который при н.у. займёт 96 кг этого газа.

Answer 1

N=96/0,048=2000моль
V=2000*0,0224=44.8м3 
Ответ 44.8 м3

Answer 2

The Ozone Layer in the Stratosphere

The ozone layer is a layer of ozone (O3) molecules located in the stratosphere, approximately 20-30 kilometers above the Earth's surface. It plays a crucial role in protecting the Earth from harmful ultraviolet (UV) radiation from the Sun. The ozone molecules absorb and scatter a significant portion of the Sun's UV-B and UV-C radiation, preventing it from reaching the Earth's surface and causing damage to living organisms.

Calculating the Volume of Ozone at Standard Conditions

To calculate the volume of ozone that 96 kg of the gas would occupy at standard conditions (n.у.), we need to use the ideal gas law equation:

PV = nRT

Where: - P is the pressure of the gas (in Pascals) - V is the volume of the gas (in cubic meters) - n is the number of moles of the gas - R is the ideal gas constant (8.314 J/(mol·K)) - T is the temperature of the gas (in Kelvin)

To find the volume, we need to know the number of moles of ozone. We can calculate this using the molar mass of ozone and the given mass of 96 kg.

The molar mass of ozone (O3) is calculated as follows: - Molar mass of oxygen (O) = 16.00 g/mol - Molar mass of ozone (O3) = 3 * (molar mass of oxygen) = 3 * 16.00 g/mol = 48.00 g/mol

Now, let's calculate the number of moles of ozone: - Moles of ozone = (mass of ozone) / (molar mass of ozone) - Moles of ozone = 96,000 g / 48.00 g/mol = 2000 mol

Next, we need to convert the number of moles to volume at standard conditions. At standard conditions, the pressure is 1 atmosphere (101,325 Pascals) and the temperature is 273.15 Kelvin.

Now, let's calculate the volume: - PV = nRT - V = (nRT) / P - V = (2000 mol * 8.314 J/(mol·K) * 273.15 K) / 101,325 Pa - V ≈ 45.63 m³

Therefore, 96 kg of ozone at standard conditions would occupy approximately 45.63 cubic meters of volume.

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