Question

Помогите уравнять реакцию: HNO3+Al=Al(NO3)3+H2O+N2O

Answer 1

6HNO3+Al=Al(NO3)3+3H2O+3NO2

Answer 2

HNO3 + Al = Al(NO3)3 + H2O + N2O

To balance this equation, we need to make sure that the number and type of atoms are the same on both sides of the equation.

Let's start by counting the number of atoms on each element:

HNO3: 1 H, 1 N, 3 O Al: 1 Al Al(NO3)3: 1 Al, 3 N, 9 O H2O: 2 H, 1 O N2O: 2 N, 1 O

Looking at the equation, we can see that there is an imbalance of nitrogen (N) and oxygen (O) atoms. To balance them, we need to adjust the coefficients in front of each compound.

Let's balance the nitrogen atoms first:

HNO3 + Al = Al(NO3)3 + H2O + N2O 1 1 1 1 ?

By comparing the number of nitrogen atoms on each side, we can see that the Al(NO3)3 compound already has 3 nitrogen atoms. Therefore, we need to put a coefficient of 3 in front of N2O:

HNO3 + Al = Al(NO3)3 + H2O + 3N2O 1 1 1 1 3

Now let's balance the oxygen atoms:

HNO3 + Al = Al(NO3)3 + H2O + 3N2O 3 ? 9 1 3

By comparing the number of oxygen atoms on each side, we can see that the HNO3 compound already has 3 oxygen atoms. Therefore, we need to put a coefficient of 3 in front of Al:

3HNO3 + Al = Al(NO3)3 + H2O + 3N2O 3 1 9 1 3

Finally, let's balance the hydrogen atoms:

3HNO3 + Al = Al(NO3)3 + H2O + 3N2O 3 6 9 1 3

By comparing the number of hydrogen atoms on each side, we can see that the HNO3 compound already has 3 hydrogen atoms. Therefore, we need to put a coefficient of 6 in front of H2O:

3HNO3 + Al = Al(NO3)3 + 6H2O + 3N2O 3 6 9 6 3

Now the equation is balanced, and the final balanced reaction is:

3HNO3 + Al = Al(NO3)3 + 6H2O + 3N2O