Question

С 24,5 г соединения,содержащего 31,84%К,28,98%Сl и 39,18%O2 по массе,нагрели при температуре выше 130 градусов с 12,8 г S.Выделившийся в результате газ пропустили через 256,5 10-% гидроксида бария.Определите состав полученного вещества(в массовых долях)

Answer 1

1)31,84/39 : 28,98/35,5 : 39,18/16
0,8 : 0,8 : 2,44
Чтобы найти целое число делим на наименьшее
0,8/0,8 : 0,8/0,8 : 2,44/0,8
1:1:3
KClO3(Хлорат калия)
2)2KClO3+3S(t >130*C)->3SO2+2KCl
m(KClO3)=24,5 г
m(S)=12,8 г
n(KClO3)=24,5/122,55=0,2 моль
n(S)=12,8/32=0,4 моль
Ищем какое в-в в недостатке
0,2/2=x/3
Надо 0,3 моль серы,а ее дано больше,хначит хлорат в недостатке,по нему и считаем
n(SO2)=0,2*3=0,6 моль
V(SO2)=0,6*22,4=13,44 л
3)Ba(OH)2+SO2->BaSO3(осадок)+H2O
m(р-р)=256,5 г
W(Ba(OH)2)=10%

m(Ba(OH)2)=256,5*0,1=25,65 г
n(Ba(OH)2)=25,65/171=0,15 моль
n(SO2)=0,6 моль
Гидроксид в недостатке,так как количество вещества равное
m(BaSO3)=0,15*217=32,55
w(Ba)=137/217=0,63=63%
w(S)=32/217=0,15=15%
w(O)=16*3/217=0,22=22%

Answer 2

Calculation of the Composition of the Resulting Substance

To determine the composition of the resulting substance, we need to analyze the given information. We have a compound with the following composition by mass:

- Potassium (K): 31.84% - Chlorine (Cl): 28.98% - Oxygen (O2): 39.18%

We also know that this compound was heated at a temperature above 130 degrees Celsius with 12.8 grams of sulfur (S). As a result, a gas was released, which was then passed through a 256.5 10-% solution of barium hydroxide (Ba(OH)2).

To determine the composition of the resulting substance, we need to consider the reactions that occurred during the heating and the subsequent reaction with barium hydroxide.

Reaction 1: Heating of the Compound

The heating of the compound with sulfur (S) can lead to various reactions depending on the specific compound. Without further information about the compound, it is difficult to determine the exact reaction that occurred. However, we can make some assumptions based on common reactions involving potassium, chlorine, oxygen, and sulfur.

One possible reaction could be the formation of potassium sulfate (K2SO4) and the release of chlorine gas (Cl2):

2KCl + SO2 -> K2SO4 + Cl2

In this reaction, potassium chloride (KCl) reacts with sulfur dioxide (SO2) to form potassium sulfate (K2SO4) and release chlorine gas (Cl2). However, this is just one possible reaction, and other reactions could also occur.

Reaction 2: Reaction with Barium Hydroxide

The gas released from the heating reaction is then passed through a solution of barium hydroxide (Ba(OH)2). This suggests that the gas could be a compound containing a halogen (such as chlorine) that can react with barium hydroxide to form a precipitate.

One possible reaction could be the formation of barium chloride (BaCl2) and the release of water (H2O):

Ba(OH)2 + 2HCl -> BaCl2 + 2H2O

In this reaction, barium hydroxide (Ba(OH)2) reacts with hydrochloric acid (HCl) to form barium chloride (BaCl2) and water (H2O). This reaction would result in the formation of a precipitate of barium chloride.

Determining the Composition of the Resulting Substance

Based on the reactions described above, we can conclude that the resulting substance is likely a compound containing potassium, sulfur, chlorine, and barium. The exact composition of the substance cannot be determined without further information about the specific reactions that occurred.

It is important to note that the given information does not provide enough details to determine the exact composition of the resulting substance in mass fractions. Additional information about the specific reactions and compounds involved would be needed for a more accurate determination.

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