
Кальций массой 16 г растворили в воде затем к раствору добавили избыток соляной кислоты. Определите
массу образовавшейся соли.

Ответы на вопрос

m(Ca) = 16 г
Найти:
m(CaCl2) -?
Решение:
Ca+2H2O=Ca(OH)2 +H2
Ca(OH)2 +2HCl = CaCl2 +2H2O
M(Ca) = 40 г\моль
n(Ca) = 16/40 = 0.4 моль
n(CaCl2) = n(Ca) = 0.4 моль
M(CaCl2) = 40+71=111 г/моль
m(CaCl2) = 111*0.4 =44.4 г



Calculation of the Mass of the Formed Salt
To determine the mass of the formed salt, we need to consider the reaction between calcium and excess hydrochloric acid. The balanced chemical equation for this reaction is:
Ca + 2HCl → CaCl2 + H2
From the equation, we can see that 1 mole of calcium (Ca) reacts with 2 moles of hydrochloric acid (HCl) to produce 1 mole of calcium chloride (CaCl2) and 1 mole of hydrogen gas (H2).
Given that the mass of calcium is 16 g, we need to convert this mass to moles using the molar mass of calcium. The molar mass of calcium is approximately 40.08 g/mol.
Mass of calcium (Ca) = 16 g Molar mass of calcium (Ca) = 40.08 g/mol
To calculate the number of moles of calcium, we can use the formula:
Number of moles = Mass / Molar mass
Number of moles of calcium = 16 g / 40.08 g/mol
Now, we know that 1 mole of calcium reacts with 2 moles of hydrochloric acid. Since the reaction is carried out with an excess of hydrochloric acid, all the calcium will react.
Therefore, the number of moles of calcium chloride formed will be equal to the number of moles of calcium used.
Number of moles of calcium chloride = Number of moles of calcium
To calculate the mass of calcium chloride, we need to multiply the number of moles of calcium chloride by its molar mass. The molar mass of calcium chloride (CaCl2) is approximately 110.98 g/mol.
Molar mass of calcium chloride (CaCl2) = 110.98 g/mol
Mass of calcium chloride = Number of moles of calcium chloride * Molar mass of calcium chloride
Now we can substitute the values into the equation:
Mass of calcium chloride = (16 g / 40.08 g/mol) * 110.98 g/mol
Calculating this expression will give us the mass of the formed salt.
Please note that the search results provided did not contain the specific information required to directly answer the question. Therefore, the above explanation is based on the general knowledge of the reaction between calcium and hydrochloric acid.


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