Question

какая масса фенолята натрия может быть получена при взаимодействии фенола массой 4,7г с раствором гидроксида натрия,содержащего 2,4г NaOH????????

Answer 1

C6H5OH + NaOH --> C6H5ONa + H2O

n(C6H5OH) = m/M = 4,7г / 94 =0.05 моль
n (NaOH) = m/M = 2.4г / 40 г/моль = 0.06 моль

по уравнению n(C6H5OH) : n(NaOH) = 1: 1 = 0.05 : 0.05 (0.06)
по уравнению гидроксида натрия требуется 0.05 моль, а его 0.06 (по расчетам), значит, гидроксид натрия в избытке. соль считаем по недостатку
n(C6H5ONa) = n(C6H5OH) = 0.05 моль
m(C6H5ONa) = n*M = 0.05 моль * 116 г/моль = 5.8г

Ответ: 5.8 г фенолята натрия 

Answer 2

Calculation of the Mass of Sodium Phenolate

To determine the mass of sodium phenolate that can be obtained from the reaction between phenol and a solution of sodium hydroxide (NaOH), we need to consider the balanced chemical equation for the reaction. The balanced equation is as follows:

C6H5OH + NaOH → C6H5ONa + H2O

From the equation, we can see that one mole of phenol reacts with one mole of sodium hydroxide to produce one mole of sodium phenolate and one mole of water.

To calculate the mass of sodium phenolate, we need to follow these steps:

1. Convert the given masses of phenol and sodium hydroxide to moles using their respective molar masses. 2. Determine the limiting reactant by comparing the moles of phenol and sodium hydroxide. 3. Use the stoichiometry of the balanced equation to calculate the moles of sodium phenolate produced. 4. Convert the moles of sodium phenolate to grams using its molar mass.

Let's calculate the mass of sodium phenolate step by step.

Step 1: Convert the masses of phenol and sodium hydroxide to moles.

Given: Mass of phenol (C6H5OH) = 4.7 g Mass of sodium hydroxide (NaOH) = 2.4 g

To convert the masses to moles, we need to divide each mass by its molar mass.

Molar mass of phenol (C6H5OH): C = 12.01 g/mol H = 1.01 g/mol (x 6) O = 16.00 g/mol Total molar mass = 94.11 g/mol

Moles of phenol = Mass of phenol / Molar mass of phenol Moles of phenol = 4.7 g / 94.11 g/mol

Molar mass of sodium hydroxide (NaOH): Na = 22.99 g/mol O = 16.00 g/mol H = 1.01 g/mol Total molar mass = 39.99 g/mol

Moles of sodium hydroxide = Mass of sodium hydroxide / Molar mass of sodium hydroxide Moles of sodium hydroxide = 2.4 g / 39.99 g/mol

Step 2: Determine the limiting reactant.

To determine the limiting reactant, we compare the moles of phenol and sodium hydroxide. The reactant that produces fewer moles of the product is the limiting reactant.

From the balanced equation, we can see that the stoichiometric ratio between phenol and sodium phenolate is 1:1. Therefore, the moles of sodium phenolate produced will be equal to the moles of phenol.

Step 3: Calculate the moles of sodium phenolate produced.

Moles of sodium phenolate = Moles of phenol

Step 4: Convert the moles of sodium phenolate to grams.

Molar mass of sodium phenolate (C6H5ONa): C = 12.01 g/mol H = 1.01 g/mol O = 16.00 g/mol Na = 22.99 g/mol Total molar mass = 91.11 g/mol

Mass of sodium phenolate = Moles of sodium phenolate x Molar mass of sodium phenolate

Now, let's calculate the mass of sodium phenolate.

Calculation:

Moles of phenol = 4.7 g / 94.11 g/mol = 0.0499 mol (approximately) Moles of sodium hydroxide = 2.4 g / 39.99 g/mol = 0.0600 mol (approximately)

Since the stoichiometric ratio between phenol and sodium phenolate is 1:1, the moles of sodium phenolate produced will be equal to the moles of phenol.

Moles of sodium phenolate = 0.0499 mol

Mass of sodium phenolate = Moles of sodium phenolate x Molar mass of sodium phenolate Mass of sodium phenolate = 0.0499 mol x 91.11 g/mol

Therefore, the mass of sodium phenolate that can be obtained from the reaction is approximately 4.54 grams.

Please note that the calculated mass is an approximation and may vary depending on the actual reaction conditions and the purity of the reactants used.