Question

При взаимодействии 60г технического железа с соляной кислотой выделилось 44,8литров водорода.Вычислите массовою долю чистого железав техническом

Answer 1

25,7 литров
по крайней мере у меня так

Answer 2

Calculation of the Mass Fraction of Iron

To calculate the mass fraction of iron in the technical grade, we need to use the information provided about the interaction of 60g of technical iron with hydrochloric acid, which resulted in the production of 44.8 liters of hydrogen gas.

To calculate the mass fraction, we need to know the molar mass of iron (Fe) and the molar mass of hydrogen (H2). The molar mass of iron is approximately 55.845 g/mol, and the molar mass of hydrogen is approximately 2.016 g/mol.

First, let's calculate the number of moles of hydrogen gas produced using the ideal gas law equation:

PV = nRT

Where: P = pressure (assume standard pressure, 1 atm) V = volume of hydrogen gas (44.8 liters) n = number of moles of hydrogen gas R = ideal gas constant (0.0821 L·atm/(mol·K)) T = temperature (assume standard temperature, 273 K)

Using the equation, we can solve for n:

n = PV / RT

Substituting the values:

n = (1 atm) * (44.8 L) / (0.0821 L·atm/(mol·K) * 273 K)

n ≈ 1.96 moles

Since the reaction between iron and hydrochloric acid is a 1:1 ratio, the number of moles of iron is also 1.96 moles.

Now, let's calculate the mass of iron:

mass of iron = number of moles of iron * molar mass of iron

mass of iron = 1.96 moles * 55.845 g/mol

mass of iron ≈ 109.38 g

Finally, let's calculate the mass fraction of iron:

mass fraction of iron = (mass of iron / mass of technical grade iron) * 100%

mass fraction of iron = (109.38 g / 60 g) * 100%

mass fraction of iron ≈ 182.3%

The calculated mass fraction of iron in the technical grade iron is approximately 182.3%.

Please note that the calculated mass fraction seems to be higher than 100%, which is not possible. There might be an error in the given information or calculation. It is recommended to double-check the values and calculations to ensure accuracy.